Question

the length of the rectabgle is 4 times its width. if the perimeter if the rectangle is 80m, find the length and breadth of rectangle

Answer 1

Answer:

Length = 4 × Breadth

Perimeter = 80m

Perimeter of rectangle = 2 ( l + b )

⇒ 2 ( 4b + b ) = 80

⇒ 2 ( 5b ) = 80

⇒ 10b = 80

⇒ b = 80 / 10 = 8 cm

⇒ Length = 4 × b ⇒ 4 × 8 = 32 cm.

Hence Length is 32 cm and Breadth is 8 cm.

Answer 2

✬ Length = 32 m ✬

✬ Breadth = 8 m ✬

Step-by-step explanation:

Given:

• Length of a rectangle is 4 times it's width.
• Perimeter of rectangle is 80 m.

To Find:

• What is the length and breadth of rectangle?

Solution: Let the width of rectangle be x m. Therefore,

• Length of rectangle = 4 times of x = 4x m

• As we know that formula for finding perimeter of rectangle is:-

★ Perimeter of rectangle = 2 ( Length + Breadth ) ★

But , Perimeter = 80 m { given }

A/q

$\implies{\rm }$ 80 m = 2 ( 4x + x )

$\implies{\rm }$ 80 m = 2 (5x)

$\implies{\rm }$ 80 m = 10x

$\implies{\rm }$ 80/10 m = x

$\implies{\rm }$ 8 m = x

So, Width of rectangle = x = 8 m and

Length of 4x = 4(8) = 32 m.

______________________

★ Verification ★

➫ 80 = 2 ( L + B )

➫ 80 = 2 ( 32 + 8 )

➫ 80 = 2 $\times$ 40

➫ 80 = 80

Verified

______________________

→ Opposite sides of a rectangle are equal.

→ Measure of each angle of rectangle is of 90°.

→ Area = Length $\times$ Breadth sq units.

→ Diagonals are also equal.