the length of the rectangle exceeds it's breadth by 4 m the perimeter of the rectangle is 40 m it's length and breadth are
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Answered by
1
Answer:
length = 12 m and breadth = 8 m
Step-by-step explanation:
let the breadth of rectangle = x m
length of rectangle = (x+4) m
peeimeter of rectangle = 2(l + b)
40 = 2(x + 4 + x)
40 = 2(2x + 4)
40 = 4x + 8
40 - 8 = 4x
32 = 4x
x = 8
breadth = 8 m
lenhth = x + 4 = 8 + 4 = 12 m
Answered by
2
Answer:
Step-by-step explanation:
Let the breadth be b
And the length be l
Given,l-b=4
l=4+b
Perimeter =40
2(l+b)=40
2(4+b+b)=40
4+2b=20
2b=20-4
b=16\2
b=8
Putting the b =8 in l=4+b we get
l=4+8=12
Hence , length is 12m and breadth is 8m
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