The length of the rectangle
exceeds its breadth by 3cm.if the length and breadth are each increased by 2 cm,then the area of new rectangle will be 70 sq.cm more than that of the given rectangle.find the length and breadth of the rectangle.
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Let the Breadth be a
Length = a + 3
Area = a^2 + 3a
New length = a + 3+ 2 = a + 5
New width = a + 2
New Area = (a + 2)(a +5)
= a^2 + 7a + 10
According to question,
(a^2 + 7a + 10) - (a^2 + 3a) = 70
=> 7a - 3a + 10 = 70
=> 4a = 60
=> a = 12
Length = 12 + 3 = 15 cm
Width = 12 cm
Length = a + 3
Area = a^2 + 3a
New length = a + 3+ 2 = a + 5
New width = a + 2
New Area = (a + 2)(a +5)
= a^2 + 7a + 10
According to question,
(a^2 + 7a + 10) - (a^2 + 3a) = 70
=> 7a - 3a + 10 = 70
=> 4a = 60
=> a = 12
Length = 12 + 3 = 15 cm
Width = 12 cm
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