The length of the rectangle exceeds its breadth by 4 units. if the perimeter is 40 units find the area of the rectangle ??? cann somebody give solution ???
Answers
Answered by
2
area - lxb
8x12
=96cm2
hope this helps
please mark it as brainliest
8x12
=96cm2
hope this helps
please mark it as brainliest
Attachments:
chayasahu:
ok thanks
can you show one more questions for me that is ,,,The sum of the digits of a two-digit number is 8. if the number formed by reversing the digit is less than the original number by 18, find the original number ?
the number is 53
mark my answer as brainliest
yeah i already marked u as brainlist
plzz check
can u solve and show me how 53 is the answer
how
i cant send photos in comments
ok can u send to my id
Answered by
4
let the breadth of the rectangle be x units
length =x+4 units
perimeter of rectangle =2(l+b)
40=2(x+x+4)
40=2(2x+4)
40=4x +8
x=40-8/4
x=32/4
x=8 units
length=8+4=12 units
area of rectangle =l*b
=12*8
=96 sq units
hope it helps
mark as branliest if u like
length =x+4 units
perimeter of rectangle =2(l+b)
40=2(x+x+4)
40=2(2x+4)
40=4x +8
x=40-8/4
x=32/4
x=8 units
length=8+4=12 units
area of rectangle =l*b
=12*8
=96 sq units
hope it helps
mark as branliest if u like
is it correct
yeah
Thanks dear
Similar questions