The length of the rectangle exceeds its width by 8cm and the area of rectangle is 240sq cm find the dimensions of the rectangle....
cutidoll:
Length = 20 and Breadth = 12
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Solution :-
Let the breadth of the rectangle be x cm
Length = (x + 8) cm
Given : Area of rectangle = 240 cm²
According to the question,
Area of rectangle = (Length × Breadth) sq. units
=> 240 = (x + 8) × x
=> 240 = x² + 8x
=> x² + 8x - 240 = 0
=> x² + 20x - 12x - 240 = 0
=> x(x + 20) - 12(x + 20) = 0
=> (x - 12) (x + 20) = 0
=> x = 12 or x = - 20
∴ x = 12 (Length is always taken positive)
Hence,
Breadth = x = 12 cm
Length = (x + 8) = (12 + 8) = 20 cm
Let the breadth of the rectangle be x cm
Length = (x + 8) cm
Given : Area of rectangle = 240 cm²
According to the question,
Area of rectangle = (Length × Breadth) sq. units
=> 240 = (x + 8) × x
=> 240 = x² + 8x
=> x² + 8x - 240 = 0
=> x² + 20x - 12x - 240 = 0
=> x(x + 20) - 12(x + 20) = 0
=> (x - 12) (x + 20) = 0
=> x = 12 or x = - 20
∴ x = 12 (Length is always taken positive)
Hence,
Breadth = x = 12 cm
Length = (x + 8) = (12 + 8) = 20 cm
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