the length of the rectangle exceeds the breadth by 6 cm . if the length is increased by 3 cm and breadth decreased by 2 cm, the area remains the same. find the length and breadth of rectangle
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Answered by
75
Hii friend,
Let the Breadth of the rectangle be X cm
Then the Length of the rectangle be (X+6) cm
Area of rectangle = Length × breadth
=> (X+6)× X= X²+6X.
Length is increased by 3 then the Length become (X+6+3) and Breadth is decreased by 2 then the Breadth become (X-2).
Area of rectangle remians same.
Therefore,
Area of the rectangle = Length × Breadth
X²+6X = (X+9) × (X-2)
X²+6X = X(X-2) +9(X-2)
X²+6X =X²-2X +9X -18
X²-X²+6X = 7X -18
7X-6X = 18
X = 18 cm
Breadth of the rectangle = X = 18 cm
And,
Length of the rectangle = (X+6) = (18+6) = 24 cm
And,
Area = L × B = 18 × 24 = 432 cm²
HOPE IT WILL HELP YOU.... :-)
Let the Breadth of the rectangle be X cm
Then the Length of the rectangle be (X+6) cm
Area of rectangle = Length × breadth
=> (X+6)× X= X²+6X.
Length is increased by 3 then the Length become (X+6+3) and Breadth is decreased by 2 then the Breadth become (X-2).
Area of rectangle remians same.
Therefore,
Area of the rectangle = Length × Breadth
X²+6X = (X+9) × (X-2)
X²+6X = X(X-2) +9(X-2)
X²+6X =X²-2X +9X -18
X²-X²+6X = 7X -18
7X-6X = 18
X = 18 cm
Breadth of the rectangle = X = 18 cm
And,
Length of the rectangle = (X+6) = (18+6) = 24 cm
And,
Area = L × B = 18 × 24 = 432 cm²
HOPE IT WILL HELP YOU.... :-)
Answered by
13
Answer:
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