The length of the rectangle exceeds the breadth by 9 CM if length and breadth of each increased by 3 cm the area of the new rectangular will be 8.4 CM square more than that of the given rectangle find the breadth and length of given rectangle
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Hello mate here is your answer,
Length of rectangle = x + 9
Breadth of rectangle = x
Formula of area = Length x breadth
=> So area of rectangle = x(x + 9) = x^2+9x
Area Of New Rectangle ::
Length of new rectangle = x + 9 +3 = x+12
Breadth of new rectangle = x + 3
So area of new rectangle = length x breadth
= (x+3) (x+12)
= x^2 + 3x + 12x + 36
= x^2 + 15x + 36
So Evaluating according to the question::
=> (x^2 + 15x + 36) - ( x^2 + 9x ) = 84
= 15x + 36 - 9x = 84
= 6x = 48
x = 8 cm
So Length = x + 9 = 17 cm
And breadth = x = 8
And area = 8 x 17 = 136 cm^2
Area of new rectangle::
=> length = x + 9 + 3 = 8 + 9 + 3 = 20cm
=> Breadth = x + 3 = 11cm
So area = length x breadth
=> 11 x 20 = 220 cm^2
So subtracting the area of both rectangles the answer we receive ::
220 - 136 = 84 cm
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