Question

The length of the rectangle is 20% more than its breadth . what will be the ratio of the area of the rectangle to that of the square whose side is equal to the breadth of the rectangle?
A) 2:1
B) 5:6
C) 6:5
D) data is inadequate

Answer 1

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Here is your answer.
Let the breadth of the rectangle is x
so length is x + 20% of x
$= x + \frac{20}{100} \times x \\ = x + \frac{x}{5} \\ = \frac{6x}{5}$
Now Area of the rectangle = L × B
$= \frac{6x}{5} \times x \\ = \frac{6x {}^{2} }{5}$
As Side of the square is equal to the breadth of the rectangle , which is x
Area of the square = Side × side
$= x \times x \\ = x {}^{2}$
The ratio of the area of the rectangle to Area of the square is
$= \frac{ \frac{6x {}^{2} }{5} }{x {}^{2} } \\ = \frac{6x {}^{2} }{5} \times \frac{1}{x {}^{2} } \\ = \frac{6}{5}$
Hence ratio is 6: 5

So Option (C) 6: 5 is your answer

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Answer 2

Answer:

6:5 is the correct answer

Step-by-step explanation:

x+20/100×x

x+x/5

6x/5

6x/5×x

x×x

x²

6x²/5/x²

6x²/5×1/x²

=6/5

=6:5

is the answer