Question

the length of the rectangle is 4 times the breadth.if The perimeter is 125 m. find The lenght and breadth of the rectangle​

Answer 1

Answer:

✮Formula used:

Perimeter of the rectangle= 2(Length+Breadth)

✮Solution:

Perimeter= 125m

Let the length be 4x and the breadth be x.

According to the condition:

2(4x+x)=125

$⇒2 ( 5x) = 125$

$⇒10x = 125$

$⇒x = \frac{125}{10}$

$⇒x = 12.5$

Therefore, The value of x is 12.5

Now, Length = 4x

⇒4×12.5

⇒50m

Breadth= x

⇒12.5m

Thus, The length is 50m and breadth is 12.5m

Answer 2

$\huge\color{pink}{\textbf{\textsf{Required \: Answer}}}$

• Length = 50 m
• Breadth = 12.5 m

⠀

$\mathbb{EXPLAINATION:-}$

★ Given,

• Length is 4 times it's breadth
• The perimeter is 125 m.
• Find the length and breadth of the rectangle.

⠀

Let the length and breadth be 4x and x respectively.

⠀

Formula of finding perimeter of rectangle:-

$\begin{gathered}\\\;\sf \pink{:\rightarrow\;perimeter\;=\;\bf{{2 \: (length + breadth)}\:}}\end{gathered}$

⠀

On putting the values, we get

$\begin{gathered}\\\;\sf {:\rightarrow\;125\;=\;\bf{{2 \: (4x + x)}\:}}\end{gathered}$

$\: \: \: \begin{gathered}\\\;\sf {:\rightarrow\;125\;=\;\bf{{2 \: (5x)}\:}}\end{gathered}$

$\: \: \: \: \: \: \begin{gathered}\\\;\sf {:\rightarrow\;\;\bf{{\frac{125}{2} \: = 5x}\:}}\end{gathered}$

[/tex]

$\: \: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;\;\bf{{ \sf{\cancel\dfrac{125}{2}}}\: = 5x}}\end{gathered}$

$\: \: \: \: \: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;\;\bf{{ \sf{{62.5}}}\: = 5x}}\end{gathered}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;\;\bf{{ \sf{\cancel\dfrac{62.5}{5}}}\: = x}}\end{gathered}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \begin{gathered}\\\;\sf{:\rightarrow\;\;\;\bf{{ \sf{{12.5}}}\: = x}}\end{gathered}$

⠀

★Therefore;

• Breadth = 12.5m

ATQ, Length is 4 times it's breadth.

• Length = 12.5 × 4 = 50m

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${\underline{\underline{\sf{\green{SOME \: IMPORTANT \: FORMULAS:-}}}}}$

⠀

✠ SQUARE:-

$\Longrightarrow$Perimeter = 4 × Side

$\Longrightarrow$Area = (Side)²

⠀

✠ RECTANGLE:-

$\Longrightarrow$Perimeter = 2 (length × breadth)

$\Longrightarrow$Area = length × breadth

⠀

✠ EQUILATERAL TRIANGLE:-

$\Longrightarrow$Perimeter = side + side + side

$\Longrightarrow$Area = 3 × side

⠀

✠ CIRCLE:-

$\Longrightarrow$Perimeter = 2πr

$\Longrightarrow$Area = πr²