Math, asked by ishika603, 1 day ago

The length of the rectangle is 4x²-3y and its breadth in-5x² +11y+3. Find its perimeter.

please tell the answer in full step.​

Answers

Answered by chandan454380
0

Answer:

-2x²+16y+6  

Step-by-step explanation:

Given: Length = 4x²-3y  

           Breadth = -5x² +11y+3

Perimeter of rectangle = 2 ( L+B )           L denotes length ,B denotes breadth

2×[4x²-3y  + ( -5x² +11y+3 )]  

2×[4x²-3y-5x²+11y+3]

2×[4x²-5x²-3y+11y+3]

2×[-x²+8y+3]  

-2x²+16y+6                          

Answered by aftabahemad
1

Final Answer:

-2x²+16y+6  

Step-by-step explanation:

As per data given in the question,

We have to determine the value of the perimeter of the rectangle if the length and breadth of rectangle are 4x²-3y and -5x² +11y+3.

As we know that,

Perimeter is nothing but the sum of length of outer boundary of the rectangle.

We know that,

Perimeter of rectangle = 2 ( L+B )          

Where, L denotes length ,B denotes breadth

So, after putting the values of L and B in the formula, we will get,

2\times [4x^2-3y  + ( -5x^2 +11y+3 )]  \\2\times [4x^2-3y-5x^2+11y+3]\\2\times [4x^2-5x^2-3y+11y+3]\\ 2\times [-x^2+8y+3] \\ -2x^2+16y+6

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