Question

the length of the rectangle is 5 metres less than twice the breadth . if the perimeter is 50 meters, find the length and breadth of the rectangle​

Answer 1

Step-by-step explanation:

Let the breadth of the rectangle be x meter.

The length of a rectangle is 5 meters less than twice the breadth. So, twice the breadth is 2*x = 2x, and 5 meters less than twice the breadth is 2x-5.

Therefore, the length of the rectangle = (2x-5)m

Formula for perimeter of a rectangle = 2(l + b)

Perimeter of the rectangle = 50m = 2(l +b)

Therefore,

2(l + b) = 2(2x-5 + x) {Substituting the values of l and b}

=50 = 2(3x-5) = 6x-10

=6x = 50 + 10 = 60

=x = 60/6 = 10m

Therefore,

Breadth = x = 10m

Length = 2x-5 = 2*10-5 = 20-5 = 15m

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Answer 2

Given :

• Length of the rectangle is 5 metre less than twice the breadth

• Perimeter of the rectangle = 50 metres

To find :

• Length and breadth of the rectangle

Solution :

Let us assume the breadth of the rectangle as x metre and length as 2x - 5 metre

Using formula,

• Perimeter of rectangle = 2(l + b)

where,

• l denotes the length of the rectangle

• b denotes the breadth of the rectangle

Substituting the given values :-

→ 50 = 2(2x - 5 + x)

→ 50 ÷ 2 = 2x - 5 + x

→ 25 = 3x - 5

→ 25 + 5 = 3x

→ 30 = 3x

→ 30 ÷ 3 = x

→ 10 = x

→ The value of x = 10

Substitute the value of x in the dimensions of rectangle which we've let :-

→ Length = 2x - 5 = 2(10) - 5 = 20 - 5 = 15 m

→ Breadth = x = 10 m

Therefore, the dimensions of rectangle are :-

• Length = 15 m
• Breadth = 10 m