Question

The length of the rectangle is 5 more than its breadth if the breadth is a metres than its area is

Answer 1

Answer:

⚠ _ Hello _ ⚠

Step-by-step explanation:

⚫ Solution ⤵

$according \: to \: question \\ b = a \: metres \\ l = a + 5 \\ area \: of \: rectangle \: = (a + 5) \times a \: \\ = > {a}^{2} + 5a$

⭐ Hope it's help⭐

Answer 2

Step-by-step explanation:

$\large\implies{\sf }$Let the breadth is "a" metres

Then, A/q

$\large\implies{\sf }$Then the length will be ( a+5)

We know that the area of Rectangle=

$length \times breadth$

So, (a+5) x a

$\large\implies{\sf }$ a²+5a