Question

The length of the rectangle is 8 m more than its breadth. If the perimeter of the rectangle is 40 m.
Find their present ages.​

Answer 1

b= x

l=x+8

ATQ

x(x+8)=240

Answer 2

Answer:

$let \: the \: breadth \: be \: x \: \\ length \: 8 + x \: \\ perimeter \: of \: rectangle \: =2(l + b)$

40 = 2(8+x+x)

40= 16+2x

2x= 40-16

2x = 24

x= 24/2

x= 12

means breadth = 12

and length = 12+8 = 20