the length of the rectangle is 8 metre and the breadth is 9 dm find the perimeter and area
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Answered by
16
perimeter of rectangle =2(l+b)
l=8m=80 dm
b=9dm
=2(80+9)
=178dm is your right answer
l=8m=80 dm
b=9dm
=2(80+9)
=178dm is your right answer
Answered by
6
length of rectangle = 8m
breadth of rectangle = 9 dm = 0•9 m
perimeter of rectangle = 2*(l+b) = 2*(8+0•9) = 2*8•9 = 17•8 m
Area of rectangle = l* b = 8 * 0•9 = 7•2 m^2
if you like it mark as brainly
breadth of rectangle = 9 dm = 0•9 m
perimeter of rectangle = 2*(l+b) = 2*(8+0•9) = 2*8•9 = 17•8 m
Area of rectangle = l* b = 8 * 0•9 = 7•2 m^2
if you like it mark as brainly
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