Question

the length of the rectangle is 8cm more than its width if the perimeter of rectangle is 44cm find the lenght and breadth of the rectangle​

Answer 1

$\: \: \: \huge\star \: \: \: { \red{ solution} : } \\ \\ let \: width \: be \: = x \\ \\ \implies \: length = 8 + x \\ \\ \green{perimeter }= 44cm \\ \\ \therefore \: p = 2 \times (l + b) \\ \\ \implies \: 44cm = 2 \times (8 + x + x) \\ \\ \implies \: \frac{44}{2} = 8cm+ 2x \\ \\ \implies \: 22 - 8 = 2x \\ \\ \implies \: 14 = 2x \\ \\ \implies \frac{14}{2} = x \\ \\ \red{ \boxed{ \blue{x = 7}}} \\ \\ \: \: \: \: \: \: \: \: width = x = 7cm \\ \\ \therefore \: \: \: \: \: length = x + 8 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 7cm + 8 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \green{length = 15cm}$

Answer 2

Answer:

The width of the rectangle = 7 cm

The length of the rectangle = 15 cm

Step-by-step explanation:

Let,

The width of the rectangle = x

The length of the rectangle = x+8

Perimeter of rectangle = 44 cm

perimeter of rectangle =

⇒ 2 (lenght + width) = 44cm

⇒ 2 × x+8 + x = 44

⇒ 2x + 16 + 2x = 44

⇒ 2x + 2x + 16 = 44

⇒ 4x + 16 = 44

⇒ 4x = 44 - 16

⇒ 4x = 28

⇒ x = 28 / 4

⇒ x = 7

The width of the rectangle = 7 cm

The length of the rectangle = x+8

⇒ x + 8

⇒ 7 + 8

⇒ 15

Therefore,

The width of the rectangle = 7 cm

The length of the rectangle = 15 cm