the length of the rectangle is 8m less than twice it's breadth if the perimeter of the rectangle is 56 m find the length and breadth
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Let length and breadth the field are l and b respectively. Then,
l=2b−8⇒2b=8+l⟶(1)
The perimeter of the rectangular field =56 m
⇒2(l+b)=56m⇒2l+2b=56m
from (1), we get
2l+8+l=56⇒3l=48⇒l=16m
∴ Length of rectangular field =16m
Breadth of rectangular field =
2
16+8
=12m
Step-by-step explanation:
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ᴘᴇʀɪᴍᴇᴛᴇʀ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ = 56 ᴍ
Solution:-
⇒ 2(l+b)=56
⇒ 2(2x−8+x)=56
⇒ 3x−8=28
⇒ 3x =28+8
⇒ x=36/3=12m
Therefore :-
ʟᴇɴɢᴛʜ(ʟ) = 2x-8 =2×12 - 8 =16 ᴍᴇᴛᴇʀs.
ʙʀᴇᴀᴅᴛʜ(ʙ) = x = 12 ᴍᴇᴛᴇʀs.
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