Math, asked by abhimd86, 8 months ago

the length of the rectangle is 8m less than twice it's breadth if the perimeter of the rectangle is 56 m find the length and breadth​

Answers

Answered by akarshitgoyal2007
6

Answer:

ANSWER

Let length and breadth the field are l and b respectively. Then,

l=2b−8⇒2b=8+l⟶(1)

The perimeter of the rectangular field =56 m

⇒2(l+b)=56m⇒2l+2b=56m

from (1), we get

2l+8+l=56⇒3l=48⇒l=16m

∴ Length of rectangular field =16m

Breadth of rectangular field =

2

16+8

=12m

Step-by-step explanation:

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Answered by Anonymous
1

ᴘᴇʀɪᴍᴇᴛᴇʀ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ = 56 ᴍ

Solution:-

⇒ 2(l+b)=56

⇒ 2(2x−8+x)=56

⇒ 3x−8=28

⇒ 3x =28+8

⇒ x=36/3=12m

Therefore :-

ʟᴇɴɢᴛʜ(ʟ) = 2x-8 =2×12 - 8 =16 ᴍᴇᴛᴇʀs.

ʙʀᴇᴀᴅᴛʜ(ʙ) = x = 12 ᴍᴇᴛᴇʀs.

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