Math, asked by Arshya2005, 1 year ago

The length of the rectangle is greater than the breadth by 3cm. If the lengths increased by 9cm and the breadth is reduced by 5cm , the area remains the same. Find the dimensions of the rectangle

Answers

Answered by svirdi933
0

Step-by-step explanation:

let the breadth x

, , , , , length x+3

atq,

(x+3+9)(x-9) = area

as area of rectangle = l×b

(x+12)(x-9)= (x+3)x

after solving

x^2-9x+12x-108=x^2+3x

x^2+3x-108-x^2-3x=0

108cm^2 area

Answered by xItzKhushix
2

Answer:

Let the breadth of rectangle be x cm.

Then the length of rectangle will be

(x + 3) cm.

We know that , area of rectangle is given by;

Area = length•breadth

Thus,

Initial area = x(x+3) cm^2

Now;

New length after increasing it by 9 cm

= (x+3+9) cm

= (x + 12) cm

Also;

New breadth after reduced it by 5cm

= (x-5) cm

Thus,

Final area = (x-5)(x+12) cm^2

According to the question;

=> Initial area = Final area

=> x(x+3) = (x-5)(x+12)

=> x^2 + 3x = x^2 + 12x - 5x - 60

=> 12x - 5x - 3x = 60

=> 4x = 60

=> x = 60/4

=> x = 15

Thus,

Breadth of the rectangle = x cm

= 15 cm

Length of the rectangle = (x+3) cm

= (15+3) cm

= 18 cm

Hence, the length and the breadth of the rectangle are 18 cm and 15 cm respectively.

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