Question

The length of the rectangle is greater than the breadth by 3cm .If the length is increased by 9cm and the breadth is reduced by 5cm the area remains the same.Find the dimensions of the rectangle

Answer 1

let breadth be x
length =x+3
area =l x b
x × x+3
x sq. +3x
x sq. + 3x =(x-5) × (x+3+9)
=x sq. +3x+9x-5x-15-45
=x sq. + 7x-60
x sq. +3x=x sq.+7x-60
x sq. form both sides will be cancelled
now we will transpose
7x+3x =60
10x=60
x =6= breadth
x+3=9=length

Answer 2

Let ,breath=X
.•.length=X+3
A1=X×[X+3]
And,
A2= (X-5)×(X+3+9)
Now,A1=A2
X×[X+3]= (X-5)×(X+3+9)
or X=15
Therefore,breath 15 and length 18 unit