Question

the length of the rectangle is greater than the breadth by 18cm . if both length and breadth are increased by 6cm then area increase by 168cm square. find the length and breadth of the rectangle.

Answer 1

Initially assume breadth =x,then length = (x+18)

Area of rectangle = length * breadth

Area = x(x+18)=x^2+18x

Area after increasing length and breadth by 6 cm was (x+6)*(x+24)

New area = x^2+30x+144 ,which is equal to previous area increased by 168

Therefore final equation was

x^2+18x+168= x^2+30x+144

Solving x=2cm ( ie.., breadth of rectangle)

And length = 2+18= 20 cm

Answer 2

here is ur ans

let breadth is x
then length is x+18
area=l*b
(x)(x+18)
x²+18x
if
(x+6)(x+24)
=x²+24x+6x+144

now acc to ques
(x²+24x+6x+144)-(x²+18x)=168
x²+12x+144=168
x² +12x=168-144
x²+12x=24
x(x+12)=24
x=24 or x=12(x=24-12)
and length =12+18 =30 or12+24 =36
hope it helps
mark brainliest