Question

The length of the rectangle is halved while its breadth is tripled what is the percentage change in the area​

Answer 1

Answer:

150%  i hope this helps u

Step-by-step explanation:

Answer 2

Solution:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large x \: units }\multiput(-1.4,1.4)(6.8,0){2}{\sf\large y \: units}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

This is the initial rectangle. The length is x units and the breadth is y units. Now the length of the rectangle is halved and becomes (x/2) units.

The breadth is tripled and becomes (3y) units.

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large x/2 \: units }\multiput(-1.4,1.4)(6.8,0){2}{\sf\large3y \: units}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Initial area: xy square units

New area: $\sf\boldff \frac{3}{2} xy$ square units

Change in area:

$\frac{3}{2}xy - xy = \frac{1}{2} xy$ square units.

Percentage change in area: $\frac{ \frac{1}{2} xy }{xy} * 100 \%$ = 50%

This is the required answer