Question

the length of the rectangle twice of its breadth if its perimeter is 45cm,find the dimensions of the rectangle?​

Answer 1

$\huge\underline\mathfrak\pink{Answer}$

Let meet of ratio of dimensions be x.

Means length be 2x and Breadth be x.

$\sf \dashrightarrow \: P=2(l+b) \\ \\\sf \dashrightarrow \: 45 \: m = 2(2x+x) \\ \\ \sf \dashrightarrow \:45 \: m = 2 \times 3x \\ \\\sf \dashrightarrow \: 45 \: m = 6x \\ \\\sf \dashrightarrow \: \frac{45 \: m}{6} = x \\ \\ \sf \dashrightarrow \: \red{7.5 \: m}$

Hence length = 2 × 7.5

= 14.0 m = 14 m

And Breadth = 1 × 7.5 m

= 7.5 m.

ㅤㅤㅤ

$\sf \therefore \: Hence, \: the \: length \: of \: rectangle \: is \: \bold{ 14 \: m} \: and \: breadth \: is \: \bold{ 7.5 \: m. }$

ㅤㅤ

$\rule{300px}{.8ex}$