Question

The length of the rectangular field is 14/15 m and its breadth is 9/10 m. Find the perimeter and area of the rectangular field.
pls answer

Answer 1

$\blue{\bold{\underline{\underline{Given}}}}$

• Length (l) = 14/15 m

• Breadth (b) = 9/10 m

$\blue{\bold{\underline{\underline{To \ Find}}}}$

• Perimeter and Area of Rectangle

$\blue{\bold{\underline{\underline{Solution}}}}$

We know that,

➦ Perimeter of Rectangle = 2(l + b)

So,

$Perimeter \: = 2( \frac{14}{15} + \frac{9}{10} ) \\ \\ \implies \: 2( \frac{14 \times 2}{15 \times 2} + \frac{9 \times 3}{10 \times 3}) \\ \\ \implies \: 2( \frac{28}{30} + \frac{27}{30} ) \\ \\ \implies \: 2 \times \frac{55}{30} \\ \\ \implies \: \frac{110}{30} = \frac{11}{3}$

Hence,

➠ Perimeter = 11/3 m

Now,

We know that,

➦ Area of Rectangle = l × b

So,

$Area \: = \frac{14}{15} \times \frac{9}{10} \\ \\ \implies \: \frac{126}{150} = \frac{63}{75}$

Hence,

➠ Area = 63/75 m²

Hence,

• Perimeter = 11/3 m

• Area = 63/75 m²

Answer 2

Answer:

THE PERIMETER OF THE FIELD IS 11/3 m

THE AREA OF THE FIELD IS 21/25 m^2

Step-by-step explanation:

GIVEN,

LENGTH OF THE RECTANGULAR FIELD   = 14/15 m

BREADTH OF THE RECTANGULAR FIELD = 9/10 M

TO FIND :-

1. PERIMETER OF THE FIELD
2. AREA OF THE FIELD

FIRST LET'S FIND PERIMETER OF THE FIELD

PERIMETER OF THE FIELD = 2(L+B)

                                              = 2(14/15 + 9/10)

                                              = [2*14/15] + [2*9/10]

                                              = 28/15 + 9/5

                                              = 28 + 27 /15

                                              = 55/15 = 11/3 m

SO, THE PERIMETER OF THE RECTANGULAR FIELD IS 11/3m

AREA OF THE FIELD = L*B

                                   = 14/15 * 9/10 ( SIMPLIFY)

                                   = 7/5 * 3/5 = 21/25 m^2

SO,THE AREA OF THE RECTANGULAR FIELD IS 21/25 m^2

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