Question

The length of the rectangular field is 50 m if its perimeter 150 m , what is its breadth?​

Answer 1

$\bf Given\begin{cases} & \sf{Length\:of\;rectangular\;field = \bf{50\;m}} \\ & \sf{Perimeter\;of\;rectangular\;field = \bf{150\;m}} \end{cases}$

To find: Breadth of rectangular field?

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☯ Let breadth of rectangular field be "x" m.

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$\setlength{\unitlength}{0.9cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 50 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large x m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

$\dag\;{\underline{\frak{As\;we\;know\;that,}}}$

$\star\;{\boxed{\sf{\pink{Perimeter_{\;(rectangle)} = 2(length + breadth)}}}}$

Therefore,

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${\underline{\sf{\bigstar\: According\:to\:the\:question\::}}}$

$:\implies\sf 2(50 + x) = 150$

$:\implies\sf (50 + x) = \cancel{\dfrac{150}{2}}$

$:\implies\sf 50 + x = 75$

$:\implies\sf x = 75 - 50$

$:\implies{\underline{\boxed{\sf{\purple{x = 25}}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Breadth\:of\;rectangular\;field\;is\; {\textsf{\textbf{25\;m}}}.}}}$

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Answer 2

Given:

• Length of rectangular field = 50 m
• Perimeter of rectangular field = 150 m

To Find:

• Breadth

Solution:

Let the breadth rectangular of rectangular field be "x".

As we know:

★ Perimeter of rectangle = 2(Length + breadth)

Putting the values:

→ 2(50 + x) = 150

→ (50 + x) = 150/2

→ 50 + x = 75

→ x = 75 - 50

→ x = 25 m

Hence,

• Breadth of rectangular field = 25 m.