Question

The length of the rectangular field is 7 times of its breadth. Its area is 1792 sq.m. Find the cost
of fencing it at the rate of Rs. 1.50 per meter.​

Answer 1

Answer:

Rs.384

Step-by-step explanation:

Let the breadth of the rectangular field be x.

Length of field = 7x

Area of rectangle = l×b

=> 1792 = 7x × x

=> 7x² = 1792

=> x² = 1792/7

=> x² = 256

=> x = 16

Hence, the length and breadth are 112m and 16m.

Perimeter of rectangle = 2(l+b)

=> Perimeter of park = 2(112+16) m = 2(128) m = 256 m

Cost of fencing per meter = Rs.1.50

Hence, total cost of fencing = Rs.(1.50×256) = Rs.384

Answer 2

Answer:

The cost  of fencing  is Rs . 384

Step-by-step explanation:

Explanation:

Given , length of the rectangular field is 7 times of its breadth .

area of the rectangle is 1792$m^{2}$

Let  x be the breadth of rectangular , so 7x be the length of the rectangle

Step1:

Area of rectangle = $l b$

⇒ x × 7x = 1792

⇒7$x^{2}$ = 1792

⇒$x^{2} = \frac{1792}{7}$ $= 256$

⇒ $x = \sqrt{256} = 16$

So , the length is 7 × 16 = 112m

breadth is x = 16 m

Step2:

Perimeter of rectangle = 2(l + b)

We have ,length = 112m and breadth  is 16m , put the value in the perimeter formula .

⇒2 (112 + 16) = 2 (128) = 256 m

Here , we have  rate of Rs. 1.50 per meter .

Therefore , the cost of 256 m = 256 × 1.50 =Rs. 384

Final answer :

Hence , the cost  of fencing  is Rs . 384

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