Question

the length of the rectangular field is 8 metres less than twice of its breadth if the perimeter of the the rectangular field is 56 metres find its length and breadth​

Answer 1

Length = 16 m

Breadth = 12 m

Step-by-step explanation:

Given:

• Length of rectangular field is 8 m less than twice the breadth.
• Perimeter of field is 56 metres.

To Find:

• What is length and breadth of field ?

Solution: Let the breadth of rectangle be x cm. Therefore,

Length = 8 less than 2x

Length = (2x – 8)m

As we know that

Perimeter of Rectangle = 2(Length + Breadth)

A/q

• Perimeter is 56 m.

$\implies{\rm }$ 56 = 2(2x – 8 + x)

$\implies{\rm }$ 56/2 = 3x – 8

$\implies{\rm }$ 28 + 8 = 3x

$\implies{\rm }$ 36 = 3x

$\implies{\rm }$ 36/3 = x

$\implies{\rm }$ 12 = x

So ,

Breadth of rectangle is 12 m.

Length of rectangle is 2(12) – 8

= 24 – 8

= 16

[ Verification ]

56 = 2(Length + Breadth)

56 = 2(16 + 12)

56 = 2 × 28

56 = 56

$\large\bold{\texttt {Verified }}$

Answer 2

Given :

●The Length= 2× Breadth - 8m

》Let the Breadth be : $\bold{x---i}$

therefore Length=$\bold{2x-8---ii}$

Also given,

●Perimeter = 56meters

━━━━━━━━━━━━━━

We know perimeter of a rectangle = 2(length+ breadth)

⇒2(length+breadth)=56m

⇒l+b=28m

⇒x+2x-8=28 m (by putting the values of length and breadth as we got in eq 1 and 2)

⇒3x= 36m

⇒x=12m

━━━━━━━━━━━━━━━

And,

2x-8m

= 24- 8m

=1 6m

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Thusthe $\red{\bold{Breadth=12m}}$and $\red{\bold{Length=16m}}$