the length of the rectangular lot is 4 m longer than the width.if the area of the lot is 12 m², what will be the length and the width of the rectangular lot?
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Area of the cross-section of the wire (A) = 4 × 10⁻⁸ m²
Resistivity (ρ) = 10 × 10⁻⁸ Ωm
Resistance (R)= 25Ω
Length of the wire (L)=?
Now,
R = ρ × L/A
⇒L = R × A/ρ
⇒L = 25 × 4 × 10⁻⁸/10 × 10⁻⁸
⇒L = 25 × 4/10 (10⁻⁸ ÷ 10⁻⁸ = 1)
⇒L = 100/10
⇒L = 10m
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