Question

The length of the rectangular park exceeds its breadth by 17 m .if the perimeter of the park is 172 m find the dimensions of the park.

Answer 1

Step-by-step explanation:

perimeter of rectangle is =2(l+b)

". ". 172m =2(17m +x)

344=17m+x

x=17-344

x=337

perimeter of rectangle=2(l+b)

". ". ". =2(17+337)

2(344)

688

Answer 2

Answer:

10.12

Step-by-step explanation:

Length = ? ( let it be X)

Breadth = 17 m

Perimeter of the rectangular park = 2(l+b) = 172 m

2(x+17) = 172 m

x+17 = 172/2

x+17 = 86

x= 86-17

x=69m. ( i.e.length=69m)

Dimensions of the park = l × b

=69×17

=1173 metre sq.

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