the length of the room is7.5 m and it's breadth.Find the ratio of length and it's breadth
Answers
Answer:
\red { Area \:of \: the \: rectangle }= \green {315 \:m^{2}}Areaoftherectangle=315m
2
Step-by-step explanation:
\begin{gathered} Ratio \: of \:length \:and \:breadth\\of\: a \: rectangle = 7:5\end{gathered}
Ratiooflengthandbreadth
ofarectangle=7:5
\begin{gathered} Let\: length (l) = 7x, \\breadth (b) = 5x \end{gathered}
Letlength(l)=7x,
breadth(b)=5x
Perimeter \:of \: the \: rectangle (P) = 72\:mPerimeteroftherectangle(P)=72m
\implies \blue {2(l+b)} = 72⟹2(l+b)=72
\implies 2(7x+5x) = 72⟹2(7x+5x)=72
\implies 2\times 12x = 72⟹2×12x=72
\implies 24x = 72⟹24x=72
\implies x = \frac{72}{24}⟹x=
24
72
\implies x = 3⟹x=3
\begin{gathered} Now, Length (l) = 7x = 7\times 3 = 21\:m\\breadth(b) = 5x = 5 \times 3 = 15 \:m \end{gathered}
Now,Length(l)=7x=7×3=21m
breadth(b)=5x=5×3=15m
\begin{gathered} Area \: of \: the \: rectangle (A) = \blue {l \times b }\\=21 \:m \times 15\:m \\= 315\:m^{2}\end{gathered}
Areaoftherectangle(A)=l×b
=21m×15m
=315m
2
Therefore.,
\red { Area \:of \: the \: rectangle }= \green {315 \:m^{2}}Areaoftherectangle=315m
2
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