The length of the seconds pendulum on the surface of the earth
is 0.95m. What will be its length on the surface of the moon?
( Emoon = (1/6) ×gEARTH] (g: acceleration due to gravity)
Answers
Answered by
0
Answer:
61m
Explanation:
TE=TM⇒2πgElE=2πgMlM⇒2πg1=2πg/6lM⇒lM=61m
Hope it helps you...Please mark me as Brainliest
Answered by
0
Explanation:
HEY MATE
HOPE IT HELPS YOU
Attachments:
Similar questions