The length of the shadow of 4 m high tree is 4.8 m find the length of another tree who is shadow is 36 m long at the same time
Answers
Answered by
2
Height of pole=AB=6 m
Length of shadow of pole =BC=4 m
Length of shadow of tower=EF=28 m
In △ABC and △DEF
∠B=∠E=90
∘
both 90
∘
as both are vertical to ground
∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)
∴△ABC∼△DEF by AA similarity criterion
We know that if two triangles are similar, ratio of their sides are in proportion
So,
DE
AB
=
EF
BC
⇒
DE
6
=
28
4
⇒DE=6×7=42 m
Hence the height of the tower is 42 m
Similar questions
Math,
1 month ago
History,
1 month ago
Social Sciences,
2 months ago
English,
2 months ago
Economy,
8 months ago