Question

the length of the shadow of a 20 m tall pole on the ground then the sun's elevation is 45 degree is​

Answer 1

Answer:20m only

As tan 45 is 1

Step-by-step explanation:

Answer 2

SOLUTION:-

Given:

AB is the tower & BC is the length of the shadow when the sun's altitude is 45°, the angle of elevation of the top of the tower from the top of the shadow is 45°.

Therefore,

In right ∆ABC,

$= > tan45 \degree = \frac{AB}{BC} \\ \\ = > 1 = \frac{20}{BC} \\ \\ = > BC = 20m$

Thus,

The height of the shadow is 20m.

Hope it helps ☺️