The length of the shadow of a 6m long pole at a certain time of the day is 3.6m. What is the height of another pole if whose shadow at the same time of the day is 54m long?
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Answer: 90m
Step-by-step explanation:
let x be the actual height of the pole
we know that tan Ф = perpendicular/base
tan Ф = 6/3.6
∴ Ф = tan inverse 6/3.6
tan (tan inverse 6/3.6) = x/54
x= 90 m
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