The length of the shadow of a pillar is √3 times its height.Find the angle of elevation of the source of light
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LINE OF SIGHT: The line of sight is a line drawn from the eye of an observer to the point in the object viewed by the observer.
ANGLE OF ELEVATION: The angle of elevation of an object viewed is the angle formed by the line of sight with the horizontal , when it is above the horizontal level.
ANGLE OF DEPRESSION:The angle of depression of an object viewed is the angle formed by the line of sight with the horizontal , when it is below the horizontal level.
•Angle of elevation and depression are always acute angles.
•If the observer moves towards the perpendicular line(Tower/ building) then angle of elevation increases and if the observer move away from the perpendicular line(Tower/ building) angle of elevation decreases.
SOLUTION:
Let BC= x m be the height of the pillar.
Let AB be the shadow of the pillar = √3x m
In ∆ABC,
tan θ = BC / AB = P/ B
tan θ = x / √3x
tan θ = 1/√3
tan θ = tan 30°
θ = 30°
Hence, the angle of elevation of the source of light is 30°.
HOPE THIS WILL HELP YOU...
ANGLE OF ELEVATION: The angle of elevation of an object viewed is the angle formed by the line of sight with the horizontal , when it is above the horizontal level.
ANGLE OF DEPRESSION:The angle of depression of an object viewed is the angle formed by the line of sight with the horizontal , when it is below the horizontal level.
•Angle of elevation and depression are always acute angles.
•If the observer moves towards the perpendicular line(Tower/ building) then angle of elevation increases and if the observer move away from the perpendicular line(Tower/ building) angle of elevation decreases.
SOLUTION:
Let BC= x m be the height of the pillar.
Let AB be the shadow of the pillar = √3x m
In ∆ABC,
tan θ = BC / AB = P/ B
tan θ = x / √3x
tan θ = 1/√3
tan θ = tan 30°
θ = 30°
Hence, the angle of elevation of the source of light is 30°.
HOPE THIS WILL HELP YOU...
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Hey!!
here is your answer,,
AB (height of pillar) = x unit
BC ( length of Shadow) = √3x unit.
Tan C = P/b
= AB/BC
= x/√3x
= 1/√3
= Tan 30
C = 30
Angle C = angle of elevation = 30°
Hope it helps you...
Thanks. ^-^
here is your answer,,
AB (height of pillar) = x unit
BC ( length of Shadow) = √3x unit.
Tan C = P/b
= AB/BC
= x/√3x
= 1/√3
= Tan 30
C = 30
Angle C = angle of elevation = 30°
Hope it helps you...
Thanks. ^-^
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