Question

The length of the shadow of a tower 153 m high is 45 m at a particular time. Find the height of an

electric pole whose shadow is 20 m long at the same time​

Answer 1

Answer:

68 metres

Step-by-step explanation:

153/45= x/20

x=68 metres

Answer 2

Let x height of the electric pole .

$\\ \\ \sf \frac{153}{45} = \frac{x}{20} \implies \frac{x}{20} = \frac{17}{5} \implies \frac{17 \times \cancel20}{ \cancel5}$

$\sf x = 17 \times 4 = 68 \: meters$

∴ Height of the Electric Pole = 68 meters

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