Question

the length of the shadow of a tower 153m high is 45m at a particular time . find the hight of an electric pole whose shadow is 20 m long at the same time.​

Answer 1

Answer:

68 metres

Step-by-step explanation:

153/45= x/20

x=68 metres

Answer 2

$\sf \frac{x}{20} = \frac{153}{45} = \frac{17}{5} \implies x = \frac{17 \times \cancel20}{ \cancel5} = 17 \times 4 = 68$

∴ Height of the Electric Pole = 68 meters

Mark as Brainliest answer please my friend