the length of the shadow of a tower in a plane ground is root3 times the height of the tower then the angle of elevation of sun is
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19
Answer:
30°
Step-by-step explanation:
Given---> Length of shadow of tower is √3 times of its height
To find---> angle of eleation of sun
Solution---> Plzzz refer the attachement
Let AB be the tower and its shadow on the ground be BC and angle of elevation of sun br α.
Let height of tower be h so,
ATQ, Length of shadow of tower
= √3 × Height of tower
= √3 × h
= √3 h
In Δ ABC,
tanα = AB / BC
=> tanα = h / √3h
=> tanα = 1 / √3
=> tanα = tan30°
=> α = 30°
So, angle of elevation of sun= 30°
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30°
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