Math, asked by yogeshchavan400, 1 year ago

the length of the Shadow of a tower is 9 metres when the sun's angle of elevation is 30digree.let us write by calculating the height of a tower.

Answers

Answered by bhagyashreechowdhury
0

Given:

The length of the shadow of the tower = 9 m

The sun's angle of elevation = 30°

To find:

The height of a tower

Solution:

We will use the following trigonometric function of a triangle to solve the given problem:  

\boxed{\boxed{\bold{tan\: \theta = \frac{Opposite\:Side}{Adjacent\:Side} }}}

 

Here from the figure attached below, in Δ ABC, we have,

θ = 30°

Opposite Side / Perpendicular = AB = height of the tower

Adjacent Side = BC = 9 m

∴   tan\: 30 = \frac{AB}{BC}

by substituting the tan 30° = \frac{1}{\sqrt{3} }  and BC = 9 m

⇒   \frac{1}{\sqrt{3}} = \frac{AB}{9}

⇒   AB = \frac{9}{\sqrt{3}}

⇒   AB = \frac{9}{1.732}

\bold{AB = 5.19\:m}

Thus, the height of a tower is 5.19 m.

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Also View:

The length of the shadow of a tower standing on level ground is found to be 2x longer when the suns alt is 30° than when it is 45°. Prove that the height of the tower is x (root3+1)m

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