Question

The length of the shadow of a tower standing on level plane is found to be 2x metres longer when the sun's altitude is 30°than when it was 45°. Prove that the height of the tower is x(√3+1)meters.​

Answer 1

Answer:

hope this will help you

Answer 2

Answer:

Let h be the height of the tower.

In ΔABC,

AB/BC=tan45∘

h/y=1

h=y

In ΔABD,

AB/BD=tan30∘

h/2x+y=1/_/3

2x+y=_/3h

2x+h=_/3h

h=2x/_/3-1

h=(_/3+1)xmeters

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