Question

the length of the shadow of three hi Pole is 3.6 what is the height of another for whose Shadow at that time is 54 metre long​

Answer 1

Answer:

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90∘ both 90∘ as both are vertical to ground

∠C=∠F  (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

So,DEAB=EFBC

⇒DE6=284

⇒DE=6×7=42 m

Hence the height of the tower is 42 m

Step-by-step explanation:

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