Question

The length of the shadows of 4m high tree is 4.8 m.find the length of another tree whose shadows is 36m long at the same time

Answer 1

Answer:

Step-by-step explanation:

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90  

∘   both 90  ∘  as both are vertical to ground

∠C=∠F  (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

So,  DE /AB =  

EF /BC ⇒  DE/ 6

​ =  28 /4  ⇒DE=6×7=42 m