Question

the length of the shorter and longer parallel sides of a trapezium are a cm and b cm respectively.If the area of trapezium is 4(a^- b^),then the height of trapezium is a)2(a-b) b)2(a+b) c)8(a-b)

Answer 1

  Area of a trapezium ABCD 

            = area (∆DFA) + area (rectangle DFEC) + area (∆CEB) 

            = (¹/₂ × AF × DF) + (FE × DF) + (¹/₂ × EB × CE) 

           = (¹/₂ × AF × h) + (FE × h) + (¹/₂ × EB × h) 



            = ¹/₂ × h × (AF + 2FE + EB) 

            = ¹/₂ × h × (AF + FE + EB + FE) 

            = ¹/₂ × h × (AB + FE) 

            = ¹/₂ × h × (AB + DC) square units.

            = ¹/₂ × (sum of parallel sides) × (distance between them)