Question

The length of the side of square A is twice the length of the side of square B. What is the ratio of the area of square A to the area of square B? 
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Answer 1

Answer:

let side of sqare B = x

then side of square A = 2x

area of B = X²

area of A = 4x²

Then ratio = A/B = 4x²/x² = 4

Answer 2

Answer:

The ratio of the area of square A to the area of square B is 4:1.

Step-by-step explanation:

Given the length of the side of square A is twice the length of the side of square B.

Let side of square B = x

And hence, the side of square A = 2x

Area of a square is given by the square of the side. i.e., $A=s^2$

Therefore, the area of square B is $A_B= x^2$

And the area of square A is $A_{A} = (2x)^2=4x^2$

The ratio of the area of square A to the area of square B is

$\frac {A_{A}}{A_B}= \frac{4x^2}{x^2}$

Cancelling the common factor, $x^{2}$ in the numerator and denominator,

$\frac {A_{A}}{A_B}=\frac{4}{1}$

Therefore, the ratio of the area of square A to the area of square B is 4:1.