The length of the sides forming right angle of a right angled triangle are 5x cm and (3x-1)cm.if the area of the triangle is 60cm2,find its hypotenuse??
Answers
Answered by
2
Area =1/2(5x)(3x-1)=60
=>3x^2-x-24=0
=>3x^2 -9x+8x-24=0
=>x=3
Then ,sides are =5(3)=15 and 3(3)-1=8
Hypotenuse=√(225+64)=17cm
Hope it helps
=>3x^2-x-24=0
=>3x^2 -9x+8x-24=0
=>x=3
Then ,sides are =5(3)=15 and 3(3)-1=8
Hypotenuse=√(225+64)=17cm
Hope it helps
Answered by
87
Answer:
Step-by-step explanation:
Solution :-
Area of triangle = 1/2 × base × height
= 1/2 × 5x × (3x - 1)
According to the Question,
15x² - 5x = 120
⇒ 3x² - x - 24 = 0
⇒ 3x² - 9 + 8x - 24 = 0
⇒ 3x(x - 3) + 8(x - 3) = 0
⇒ (x - 3) (3x + 8) =
⇒ x = 3, - 8/3 (As x can't be negative)
⇒ x = 3
AB = 5 × 3 = 15 cm
BC = 3x - 1 = 9 - 1 = 8 cm
AC = √15² + 8²
= √225 + 64
= √289
= 17 cm
Hence, the hypotenuse is 17 cm.
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