Question

the length of the sides (in cm) of a right triangle are x, x+1 and x+2. find the length of the sides of the triangle. what is its area?​

Answer 1

Explanation:

here is your answer please check it out

Answer 2

Answer:

6 sq.units

Explanation:

By the Pythagoras theorem,

(x+2)2 = x2 + (x+1)2

x2+4x+4 = x2 + x2+2x+1

x2+4x+4 = 2x2+2x+1

0 = 2x2-x2 + 2x-4x +1-4

0 = x2 - 2x - 3

0 = x2 +x -3x -3

0 = x(x+1) - 3(x+1)

0 = (x+1)(x-3)

0 = x+1 0 = x-3

-1 = x. 3 = x

But length can't be negative.

therefore, x = 3

Area of triangle = 1/2*base*height

= 1/2*x*(x+1)

= 1/2*3*(3+1)

= 1/2*3*4

= 3*2

= 6 sq.units

Hence,area of triangle is 6sq.units.

hope it helps u....