Math, asked by tanaypk, 9 months ago

the length of the sides of a right angle 2 x -1, 4x, and 4 x + 1 where X is greater than zero find the value of x​

Answers

Answered by priya1352
1

Step-by-step explanation:

(4x+1)^2=(4x^2)+(2x-1)^2

16x^2+1+8x=16x^2+4x^2+1-4x

8x=4x^2-4x

4x^2=12x

x=3

Answered by rvvsarma
1

Answer:

3

Step-by-step explanation:

Hypotenuse=4x+1

remaining two sides are 4x, 2x-1

By Pythagoras theorem,

(hypotenuse)^2 = (1st side)^2 + (2nd side)^2

(4x+1)^2 = (4x)^2 + (2x-1)^2

16x^2 +8x + 1 = 16x^2 + 4x^2 - 4x + 1

8x = 4x^2 - 4x

2x = x^2 - x

2 = x-1

x=3.

the value of x = 3.

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