the length of the sides of a right angle 2 x -1, 4x, and 4 x + 1 where X is greater than zero find the value of x
Answers
Answered by
1
Step-by-step explanation:
(4x+1)^2=(4x^2)+(2x-1)^2
16x^2+1+8x=16x^2+4x^2+1-4x
8x=4x^2-4x
4x^2=12x
x=3
Answered by
1
Answer:
3
Step-by-step explanation:
Hypotenuse=4x+1
remaining two sides are 4x, 2x-1
By Pythagoras theorem,
(hypotenuse)^2 = (1st side)^2 + (2nd side)^2
(4x+1)^2 = (4x)^2 + (2x-1)^2
16x^2 +8x + 1 = 16x^2 + 4x^2 - 4x + 1
8x = 4x^2 - 4x
2x = x^2 - x
2 = x-1
x=3.
the value of x = 3.
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