The length of the sides of a right angled triangle are three consecutive terms of a arithmetic sequence with common difference 2. Find the ares of the triangle.
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Answer:
three sides of the triangle will be
x+2, x+4, x+6
since they are the sides of a right angle triangle
(x+6)^2=(x+2)^2 + (x+4)^2
x^2 +12x + 36 = x^2 +4x + 4 + x^2 +8x + 16
x^2- 2x^2 +36 - 20 = 0
x^2 = 16
x = 4
area of the triangle = (1/2)×(x+2)×(x+4)
=(1/2)×6×8= 24 Ans
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