the length of the sides of a right triangle are (2x-1)m, (4x)m and (4x+1)m,where x>0.find value of x and the area of triangle
Answers
Answered by
0
His answer is easy to draw
Answered by
0
Answer:
x=3
Step-by-step explanation:
(2x-1)^2 + (4x)^2 = (4x+1)^2
4x^2+1 - 4x+ 16x^2 = 16x^2 +1 +8x
20x^2 - 4x + 1 = 16x^2 +1 +8x
20x^2 - 4x + 1 - 16x^2 - 1 - 8x = 0
4x^2 - 12x= 0
4x(x - 3) = 0
x(x - 3) = 0 (Dividing both sides by 4)
If the products of both sides is 0, then one of them has to be 0.
x = 0 or x - 3 = 0
x = 0 or x = 3
Rejecting 0 as x>0
Hence, x = 3
Similar questions