Question

The length of the sides of a right triangle are 8 cm. and 15 c.m.
Find the length of its hypotenuse​

Answer 1

Answer:

$h = \sqrt{ {15}^{2} + {8}^{2} } \\ = \sqrt{225 + 64} \\ = \sqrt{289 } \\ h = 17cm$

Answer 2

Given: The length of the sides of a right ∆ are 8 cm and 15 cm.

Need to find: The length of It's Hypotenuse?

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❍ Let's say, that the hypotenuse be x cm and other sides be y and z cm respectively.

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$\underline{\bigstar\:{\pmb{\sf{According\: to\; Pythagoras \;theorem :}}}}$

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$\dashrightarrow\sf \Big\{Hypotenuse\Big\}^2 = \Big\{Base\Big\}^2 + \Big\{Height\Big\}^2 \\\\\\\dashrightarrow\sf x^2 = y^2 + z^2 \\\\\\\dashrightarrow\sf x^2 = 8^2 + 15^2\\\\\\\dashrightarrow\sf x^2 = 64 + 225\\\\\\\dashrightarrow\sf x^2 = 289\\\\\\\dashrightarrow\sf x = \sqrt{289}\\\\\\\dashrightarrow\underline{\boxed{\pmb{\frak{x = 17\; cm}}}}\;\bigstar$

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$\therefore{\underline{\textsf{Hence, the required length of Hypotenuse is \textbf{17 cm}.}}}$