Question

The length of the sides of a right triangle are 8 cm. and 15 c.m. Find the length of its hypotenuse

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Answer 1

Answer:

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➬ Base (BC) = 8 cm. ➬ Perpendicular (AB) = 15 cm. ➬ Hypotenuse (AC) = ? ➬ AC = 17 Cm.

OR

According to the Pythagoras theorem, we have (Hypotenuse)2 = (Base)2 + (Height)2 Let c be hypotenuse and a and b be other two legs of right angled triangle Then we have

c2 = a2 + b2

c2 = 82 + 152

c2 = 64 + 225= 289

c = 17 cm

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Answer 2

GIVEN :-

Base of right angled triangle = 8 cm.

Perpendicular of right angled triangle = 15 cm.

TO FIND :-

The hypotenuse of right angled triangle.

SOLUTION :-

➬ Base (BC) = 8 cm.

➬ Perpendicular (AB) = 15 cm.

➬ Hypotenuse (AC) = ?

☯ By Pythagoras theorem,

➬ AB² + BC² = AC²

➬ AC² = AB² + BC²

➬ AC² = $15^{2} +8^{2}$

➬ AC² = $225+64$

➬ AC² = $289$

➬ AC = $\sqrt{289\\}$

➬ AC = $17 cm$

Hence hypotenuse of right angled triangle is 17 cm.

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