Question

The length of the sides of a triangle are (2a+1)cm, (3a+2)cm and (4a-1)cm find the perimeter of the triangle in terms of a

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Perimeter\:of\:rectangle=9a+2 cm}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given : }} \\ : \implies \text{Sides \: of \: triangle = (2a + 1),(3a + 2),(4a - 1)} \\ \\ \red {\underline \bold{To \: Find: }} \\ : \implies \text{Perimeter \: of \: triangle = ?}$

• According to given question :

$: \implies \text{ Perimeter \: of \: triangle =side( a) + side(b )+ side(c)} \\ \\ : \implies Perimeter = 2a + 1 + 3a + 2 + 4a - 1 \\ \\ : \implies Perimeter = 2a + 3a + 4a + 1 + 2 - 1 \\ \\ \green{ : \implies \text{Perimeter = (9a + 2 )cm}}$

Answer 2

$\huge{\underline{\underline{\pink{\mathfrak{AnSwEr :}}}}}$

$\large{\gray{\sf{Perimeter \: = \: (9a \: + \: 2)cm}}}$

$\huge{\underline{\underline{\blue{\mathfrak{Explanation :}}}}}$

Sides are :

(2a + 1)cm , (3a + 2)cm , (4a - 1) cm

=================================

As we know formula for Perimeter of Triangle is :

$\large{\underline{\boxed{\orange{\sf{Perimeter \: = \: Sum \: of \: Sides}}}}}$

________________[Putting Values]

$\rightarrow {\sf{Perimter \: = \: 2a \: + \: 1 \: + \: 3a \: + \: 2 \: + \: 4a \: - \: 1}}$

$\rightarrow {\sf{Perimeter \: = \: 9a \: + \: 3 \: - \: 1}}$

$\rightarrow {\sf{Perimeter \: = \: 9a \: + \: 2}}$

$\large \implies {\boxed{\boxed{\tt{\red{Perimeter \: = \: (9a \: + \: 2)cm}}}}}$